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Proof step 259 from proof inv-link (previous step)

dirs[ino0] = mkdir(m0, md0, # links(ino0, dirs), m3, entries0), dent = negdentry(p.last), inode = getinode(mkdentry(str, entries0[str]).ino, dirs, files), mkdentry(str, entries0[str]).dentry?, afs-cons(dirs, files), ispath(q, ROOT_INO, ino0, dirs, files), of-cons(of, dirs, files), px(user, md0), px-parent(user, q, ROOT_INO, dirs, files), str ∈ entries0, entries0[str] ∈ files, ino0 ∈ dirs, links(ino0, dirs) ≠ ∅ ∨ ino0 = ROOT_INO, ⌊err0⌋ ∨ err0 = ESUCCESS ∧ ispath(parent(p), ROOT_INO, ino1, dirs, files) ∧ px-parent(user, parent(p), ROOT_INO, dirs, files) ∨ err0 = ENOENT ∧ ¬ ispath(parent(p), ROOT_INO, dirs, files) ∨ err0 = EACCESS ∧ p ≠ p.head ' ∧ p' ⊑ parent(parent(p)) ∧ ispath(p', ROOT_INO, dirs, files) ∧ ¬ px(user, p', ROOT_INO, dirs, files) ⊦ ⟪skip; if err0 = ESUCCESS then {c_inode := getinode(mkdentry(str, entries0[str]).ino, dirs, files); afs_link#(mkdentry(str, entries0[str]); inode, c_inode, dent, err0, dirs, files; asynced)}⟫ (of-cons(of, dirs, files) ∧ afs-cons(dirs, files)), err0 = ESUCCESS, p = ε, entries0[str] ∈ dirs

Heuristic symbolic execution applied rule skip right

And obtained the following new goals

Rule argument

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