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Proof step 262 from proof inv-link (previous step)

dirs[ino0] = mkdir(m0, md0, # links(ino0, dirs), m3, entries0), c_inode = inode, err = ESUCCESS, err0 = ESUCCESS, ino = mkdentry(str, entries0[str]).ino, inode = getinode(ino, dirs, files), inode0 = mkinode(ino0, md0, true, # links(ino0, dirs), m3, m0), mkdentry(str, entries0[str]).dentry?, afs-cons(dirs, files), ispath(q, ROOT_INO, ino0, dirs, files), of-cons(of, dirs, files), pre-iget(ino, dirs, files), px(user, md0), px-parent(user, q, ROOT_INO, dirs, files), str ∈ entries0, ino0 ∈ dirs, links(ino0, dirs) ≠ ∅ ∨ ino0 = ROOT_INO ⊦ p = ε, err = ESUCCESS ∧ inode.directory, p ≠ ε ∧ p ≠ ε

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ mkdentry(str, m).dentry?; (s)% ⊦ valid-ino(ino, dirs, files) ↔ ino ∈ dirs ∨ ino ∈ files; (s)% ⊦ pre-iget(ino, dirs, files) ↔ valid-ino(ino, dirs, files); (s)% ⊦ mkdentry(str, m).ino = m; (s)