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Proof step 30 from proof inv-put-inode (previous step)

# links(m0, dirs) = 0, files[m0] = mkfile(m, md, 0, content), of[n] = mkfile(m0, mode, m1), afs-cons(dirs, files), afs-cons(dirs, files -- m0), of-cons(of, dirs, files), n ∈ of, m0 ∈ files ⊦ m0 = ROOT_INO, ∃ n. n ∈ of ∧ of[n].ino = m0

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: n abort: F discard: F computed: T

Additional information

Used simplifier rules: ⊦ mkfile(m, mode, m0).ino = m; (s) Used terms: n