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Proof step 147 from proof inv-renam (previous step)

dirs[entries0[str]] = mkdir(m, md, # links(entries0[str], dirs), m2, entries), dirs[ino1] = mkdir(m0, md0, # links(ino1, dirs), m3, entries0), dent = negdentry((q0 + str0 ').last), err = ESUCCESS, err0 = EACCESS, err1 = ESUCCESS, inode = getinode(ino, dirs, files), inode0 = mkinode(ino1, md0, true, # links(ino1, dirs), m3, m0), p_inode = getinode(mkdentry(str, entries0[str]).ino, dirs, files), mkdentry(str, entries0[str]).dentry?, inode.directory, dom of < ino2, afs-cons(dirs, files), ispath(q, ROOT_INO, ino1, dirs, files), ispath(q0, ROOT_INO, ino, dirs, files), of-cons(of, dirs, files), pre-iget(ino, dirs, files), pw(user, md0), pw(user, md), px(user, md0), px-parent(user, q, ROOT_INO, dirs, files), px-parent(user, q0, ROOT_INO, dirs, files), ino1 ∈ dirs, entries0[str] ∈ dirs, str ∈ entries0, links(ino1, dirs) ≠ ∅ ∨ ino1 = ROOT_INO ⊦ ⟪skip⟫ (of-cons(of, dirs, files) ∧ afs-cons(dirs, files)), q0 + str0 ' = ε, entries0[str] = ROOT_INO, px(user, inode.meta), q + str ' ⊑ q0 + str0 '

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ p + str ' ≠ ε; (s)%a: ⊦ (p + p0) + p1 = p + p0 + p1; from specification list[path]% ⊦ pre-iget(ino, dirs, files) ↔ valid-ino(ino, dirs, files); (s)% ⊦ valid-ino(ino, dirs, files) ↔ ino ∈ dirs ∨ ino ∈ files; (s)%⊦ getinode(ino, dirs, files) = (ino ∈ dirs ⊃ mkinode (ino, dirs[ino].meta, true, dirs[ino].nlink, dirs[ino].nsubdirs, dirs[ino].size) ;mkinode (ino, files[ino].meta, false, files[ino].nlink, 0, files[ino].size) ); (s)% ⊦ mkdentry(str, m).dentry?; (s)