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Proof step 82 from proof inv-renam (previous step)

p_inode.ino = ROOT_INO, isdir ↔ p_inode.directory, dirs[ino1] = mkdir(m0, md0, # links(ino1, dirs), m3, entries0), err = EACCESS, err0 = ESUCCESS, err1 = ESUCCESS, ino = mkdentry(str, entries0[str]).ino, inode = p_inode0, isdir, old_dent_inode = p_inode, p_inode = getinode(ino, dirs, files), mkdentry(str, entries0[str]).dentry?, dom of < ino0, afs-cons(dirs, files), ispath(q, ROOT_INO, ino1, dirs, files), of-cons(of, dirs, files), pre-iget(ino, dirs, files), pw(user, md0), px(user, md0), px-parent(user, q, ROOT_INO, dirs, files), str ∈ entries0, ino1 ∈ dirs, links(ino1, dirs) ≠ ∅ ∨ ino1 = ROOT_INO ⊦ ⟪skip⟫ (of-cons(of, dirs, files) ∧ afs-cons(dirs, files)), p = ε, q + str ' ⊑ p

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ mkdentry(str, m).ino = m; (s)%⊦ getinode(ino, dirs, files) = (ino ∈ dirs ⊃ mkinode (ino, dirs[ino].meta, true, dirs[ino].nlink, dirs[ino].nsubdirs, dirs[ino].size) ;mkinode (ino, files[ino].meta, false, files[ino].nlink, 0, files[ino].size) ); (s)% ⊦ pre-iget(ino, dirs, files) ↔ valid-ino(ino, dirs, files); (s)% ⊦ valid-ino(ino, dirs, files) ↔ ino ∈ dirs ∨ ino ∈ files; (s)% ⊦ mkdentry(str, m).dentry?; (s)