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Proof step 597 from proof inv-write (previous step)

files0[m] = mkfile(m1, md, # links(m, dirs), content0), of[fd] = mkfile(m, mode, m0), dirs1 = dirs, err = ESUCCESS, err0 = ESUCCESS, files1 = files0[m, mkfile(m1, md, # links(m, dirs), content0 upto m1)], ino = m1, ino0 = m0 + n, ino1 = m0 + ino4, ino2 = 0, ino4 = 0, ino4 = ino5, ino6 = m0, inode = mkinode(m, md, false, # links(m, dirs), 0, m1), ¬ isdir0, n0 = ino4, dom of < ino3, afs-cons(dirs, files0), afs-cons(dirs, files), of-cons(of, dirs, files0), of-cons(of, dirs, files), fd ∈ of, m ∈ files0, n ≤ # buf0 ⊦ n = 0, mode ≠ MODE_W ∧ mode ≠ MODE_RW, m1 % VFS_PAGE_SIZE ≠ 0 ∧ m1 / VFS_PAGE_SIZE ∈ content0, err = ESUCCESS ∧ ¬ isdir, of-cons(of[fd, of[fd].pos:= (m0 + n0)], dirs, files) ∧ dom of[fd, of[fd].pos:= (m0 + n0)] < ino3 ∧ afs-cons(dirs, files)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: of-cons-reduce: ⊦ of-cons(of0, dirs0, files0) → ( of-cons(of1, dirs1, files1) ↔ (∀ n. (n ∈ of0 → of0[n].ino ∈ files0) → n ∈ of1 → of1[n].ino ∈ files1));% ⊦ of[fd] = file ∧ fd ∈ of → of[fd, file] = of; (s)% ⊦ mkfile(m, mode, m0).pos:= m2 = mkfile(m, mode, m2); (s)% ⊦ fd ∈ of → dom of ++ fd = dom of; (s)% ⊦ dom of[fd, file] = dom of ++ fd; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)