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Proof step 87 from proof write-loop-0 (previous step)

VFS_PAGE_SIZE = n0 + (ino2 + ino5) % VFS_PAGE_SIZE, files[m] = mkfile(m3, md0, m4, content), buf = copy(buf0, ino5, zeropage, (ino2 + ino5) % VFS_PAGE_SIZE, min(ino1 - ino2 + ino5, n0)), err = ESUCCESS, inode = mkinode(m, md, boolvar, m0, m1, m2), n = min(ino1 - ino2 + ino5, n0), pageno = (ino2 + ino5) / VFS_PAGE_SIZE, m ∈ files, ino5 + min(ino1 - ino2 + ino5, n0) ≤ # buf0, ino2 + ino5 ≤ ino1, (ino2 + ino5) % VFS_PAGE_SIZE + min(ino1 - ino2 + ino5, n0) ≤ VFS_PAGE_SIZE, (ino2 + ino5) % VFS_PAGE_SIZE + min(ino1 - ino2 + ino5, n0) ≤ # zeropage, ino1 ≥ ino2 + ino5, ino5 = 0 → files = files1 ⊦ [ino5 := ino5 + n] (ino5 = 0 → files[inode.ino, files[inode.ino].content:= files[inode.ino].content[pageno, buf]] = files1), VFS_PAGE_SIZE = 0, min(ino1 - ino2 + ino5, n0) = 0, (ino2 + ino5) / VFS_PAGE_SIZE ∈ content

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = 0 ↔ m = 0 ∧ n = 0; (ws)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic