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Proof step 279 from proof write-term (previous step)

dirs0 = dirs, err = ESUCCESS, afs-cons(dirs, files), of-cons(of, dirs, files), fd ∈ of, n ≤ # buf, of[fd].mode ≠ MODE_W → fd ∈ of ⊦ n = 0, ∃ inode, isdir. true, of[fd].mode ≠ MODE_W ∧ of[fd].mode ≠ MODE_RW

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ fd ∈ of → of[fd] = (∅)[fd]; (s)