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Proof step 2 from proof dir-not-open (previous step)

afs-cons(dirs, files), is-open(ino, of), of-cons(of, dirs, files), ino ∈ dirs ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
afs-cons(dirs, files), is-open(ino, of), of-cons(of, dirs, files), ino ∈ dirs ⊦

Rule argument

Additional information