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Proof step 15 from proof min-le-diff-third (previous step)

n2 ≤ n2 - (n1 < n2 ⊃ n1;n2) ⊦ n0 = 0, n1 = 0, n2 = 0, n0 < (n1 < n2 ⊃ n1;n2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
n2 ≤ n2 - (n1 < n2 ⊃ n1;n2), n1 ≤ n0 ⊦ n0 = 0, n1 = 0, n2 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ 0 ↔ m = 0; (s)% ⊦ m - m = 0; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)