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Proof step 17 from proof min-le-diff-third (previous step)

n2 = n3 + (n1 < n2 ⊃ n1;n2), n1 ≤ n0, n2 ≤ n3, (n1 < n2 ⊃ n1;n2) ≤ n2 ⊦ n0 = 0, n1 = 0, n2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
n2 = n3 + (n1 < n2 ⊃ n1;n2), (n1 < n2 ⊃ n1;n2) ≤ n2, n2 ≤ n3, n1 ≤ n0, (n1 < n2 ⊃ n1;n2) ≤ n3 ⊦ n0 = 0, n1 = 0, n2 = 0

Rule argument

Additional information

Used simplifier rules: let: ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward) from specification nat