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Proof step 208 from proof truncate-inv (previous step)

⟨dirs[ino].meta := inode.meta⟩ (dirs = dirs0 ∧ files = files0), VFS_PAGE_SIZE = n0 + m0 % VFS_PAGE_SIZE, files1[ino4] = mkfile(m0, md, # links(ino4, dirs), content0), files0[ino4] = mkfile(m, md0, m1, content1), files = files1 [ino4, mkfile(m0, md, # links(ino4, dirs), content0[m0 / VFS_PAGE_SIZE, fill(content0[m0 / VFS_PAGE_SIZE], zero, m0 % VFS_PAGE_SIZE, n0)] upto m0) ], ino = inode.ino, inode = mkinode(ino4, md, false, # links(ino4, dirs), 0, m0), afs-cons(dirs0, files0), afs-cons(dirs, files1), files1 ~ files0, ino4 ∈ files1, m0 / VFS_PAGE_SIZE ∈ content0, ino ∈ dirs ⊦ m0 % VFS_PAGE_SIZE = 0, files1 -- ino4 = files0 -- ino4, ino ∈ files

Heuristic symbolic execution applied rule assign left

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ files[ino, af][ino0] = (ino0 = ino ∧ ino ∈ files ⊃ af;files[ino0]); (s)%⊦ mkfile(m, md, m0, content) = mkfile(m1, md0, m2, content0) ↔ m = m1 ∧ md = md0 ∧ m0 = m2 ∧ content = content0; (ws)%ino ∈ files ⊦ files[ino, af] -- ino = files -- ino; (s)