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Proof step 48 from proof write-inv-post (previous step)

files1 -- ino = files0 -- ino, (content0.stream from m1)[n4] = zero, files1[ino] = mkfile(m1, md1, # links(ino, dirs), content1), files0[ino] = mkfile(m1, md1, n2, content0), n3 = n4 + m1, n3 < n0 + n, m1 < # buf + n0, n3 < # buf + n0, m1 < n1, n3 < n1, n3 < n0, m1 < n0 + n, m1 < n0, afs-cons(dirs, files1), ino ∈ files0, ino ∈ files1, m1 ≤ n3, n0 + n ≤ n1, n1 ≤ # buf + n0, n ≤ # buf ⊦ n = 0, zero = getbyte(n3, content0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 49:
files1 -- ino = files0 -- ino, (content0.stream from m1)[n4] = zero, files1[ino] = mkfile(m1, md1, # links(ino, dirs), content1), files0[ino] = mkfile(m1, md1, n2, content0), m1 < # buf + n0, m1 < n1, n4 + m1 < n1, n4 + m1 < n0, m1 < n0 + n, m1 < n0, afs-cons(dirs, files1), ino ∈ files0, ino ∈ files1, n0 + n ≤ n1, n1 ≤ # buf + n0, n ≤ # buf ⊦ n = 0, zero = getbyte(n4 + m1, content0)

Rule argument

Additional information

Used simplifier rules: fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat% ⊦ m + n < m0 → m + n < m0 + n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)