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Proof step 66 from proof write-inv-post (previous step)

files1 -- ino = files0 -- ino, files0[ino] = mkfile(m1, md1, n2, content0), files1[ino] = mkfile(m1, md1, # links(ino, dirs), content1), content0.stream from m1 = σ⊥, n3 < m1, n0 < m1, afs-cons(dirs, files1), ino ∈ files1, ino ∈ files0, n0 + n ≤ m1, n ≤ # buf, n1 ≤ # buf + n0, n0 + n ≤ n1, n0 ≤ n3 ⊦ (n0 + n ≤ n3 ⊃ getbyte(n3, content0);buf[n3 - n0]) = ((⌜buf⌝ to n) + (content0.stream from n0 + n))[n3 - n0], n = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 67:
files1 -- ino = files0 -- ino, files1[ino] = mkfile(m1, md1, # links(ino, dirs), content1), files0[ino] = mkfile(m1, md1, n2, content0), content0.stream from m1 = σ⊥, n3 = n4 + n0, n0 < m1, n3 < m1, afs-cons(dirs, files1), ino ∈ files0, ino ∈ files1, n0 ≤ n3, n0 + n ≤ n1, n1 ≤ # buf + n0, n ≤ # buf, n0 + n ≤ m1 ⊦ (n0 + n ≤ n3 ⊃ getbyte(n3, content0);buf[n4]) = ((⌜buf⌝ to n) + (content0.stream from n0 + n))[n4], n = 0

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n3, n0, n5]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n3, n0, n5