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Proof step 5 from proof inv-unmap (previous step)

# lpt = # avol, m = m1, m0 = m2, m2 < # avol, awbuf-inv(avol, bleb), synced(avol) ⊦ ⟪avol[m0] := unmapped⟫ (awbuf-inv(avol, bleb) ∧ # lpt = # avol), buffered(m2) = bleb

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ bleb ≠ buffered(n) ∧ awbuf-inv(avol, bleb) → awbuf-inv(avol[n, unmapped], bleb); (s)% ⊦ # avol[n, aleb] = # avol; (s)