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Proof step 6 from proof synced-unmap (previous step)

⟨avol[m0] := unmapped⟩ (avol = avol1), # lpt = # avol, m = m1, m0 = m2, m2 < # avol, awbuf-inv(avol, bleb), synced(avol), avol0 ↓ avol1 ⊦ buffered(m2) = bleb, synced(avol1), avol0 ↓ avol

Heuristic symbolic execution applied rule assign left

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → (n ≤ m ↔ false); (s)%n < # avol0 ⊦ avol1 ↓ avol0[n, aleb] → (avol1 ↓ avol0 ↔ avol1[n] ↓ avol0[n]); (ss)% ⊦ synced(avol) → synced(avol[n, unmapped]); (s)