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Proof step 2 from proof down-arrow-size (previous step)

avol1 ↓ avol0 ⊦ # avol1 = # avol0 ↔ true

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: down-arrow-def: ⊦ avol1 ↓ avol0 ↔ # avol1 = # avol0 ∧ (∀ n. n < # avol0 → avol1[n] ↓ avol0[n]);