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Proof step 1 from proof down-arrow-size0 (conclusion)

⊦ avol1 ↓ avol0 ∧ # avol0 = n → (n = # avol1 ↔ true)

System applied rule normalize

And obtained the following new goals

Proof step 2:
# avol0 = n, avol1 ↓ avol0 ⊦ n = # avol1 ↔ true

Rule argument

Additional information