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Proof step 2 from proof inv-is-aligned-notbuffer (previous step)

avol[m] = mapped(buf), m < # avol, awbuf-inv(avol, buffered(n)) ⊦ is-aligned(# buf, EB_PAGE_SIZE) ↔ true, n = m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
avol[n] = mapped(buf0), avol[m] = mapped(buf), n < # avol, m < # avol, ∀ n0. n0 < # avol ∧ avol[n0].mapped? → # avol[n0].data ≤ LEB_SIZE ∧ (n0 ≠ n → is-aligned(# avol[n0].data, EB_PAGE_SIZE)) ⊦ n = m, is-aligned(# buf, EB_PAGE_SIZE)

Rule argument

Additional information

Used simplifier rules: awbuf-inv-def: ⊦ awbuf-inv(avol, bleb) ↔ ¬ ¬ ( (∀ n. n < # avol ∧ avol[n].mapped? → # avol[n].data ≤ LEB_SIZE ∧ ( buffered(n) ≠ bleb → is-aligned(# avol[n].data, EB_PAGE_SIZE))) ∧ (bleb ≠ nobuffer → bleb.leb < # avol ∧ avol[bleb.leb].mapped?));% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ aleb.mapped? ↔ (∃ buf. aleb = mapped(buf)); (as)% ⊦ buffered(m).leb = m; (s)% ⊦ nobuffer ≠ buffered(m); (s)% ⊦ buffered(m) = buffered(m0) ↔ m = m0; (s)