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Proof step 9 from proof inv-unmap (previous step)

n0 < # avol ∧ avol[n0].mapped? → # avol[n0].data ≤ LEB_SIZE ∧ is-aligned(# avol[n0].data, EB_PAGE_SIZE), bleb ≠ nobuffer → bleb.leb < # avol ∧ avol[bleb.leb].mapped? ⊦ bleb = buffered(n), buffered(n0) = bleb, n0 = n, (n0 < # avol ∧ avol[n, unmapped][n0].mapped? → # avol[n0].data ≤ LEB_SIZE ∧ is-aligned(# avol[n0].data, EB_PAGE_SIZE)) ∧ (bleb ≠ nobuffer → bleb.leb < # avol ∧ avol[n, unmapped][bleb.leb].mapped?)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
avol[n, unmapped][bleb.leb] = unmapped, avol[bleb.leb] = mapped(buf), bleb.leb < # avol, n0 < # avol ∧ avol[n0].mapped? → # avol[n0].data ≤ LEB_SIZE ∧ is-aligned(# avol[n0].data, EB_PAGE_SIZE) ⊦ bleb = nobuffer, bleb = buffered(n), buffered(n0) = bleb, n0 = n

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ aleb.mapped? ↔ aleb ≠ unmapped; (ss)% ⊦ aleb.mapped? ↔ (∃ buf. aleb = mapped(buf)); (as)% ⊦ m ≠ n → avol[n, aleb][m] = avol[m]; (s)