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Proof step 1 from proof abs-mapped-is-mapped (conclusion)

n < # avol ⊦ abs(avol, bleb, wbuf, avol0, rofs) ∧ avol[n] = mapped(buf) → (avol0[n].mapped? ↔ true)

System applied rule normalize

And obtained the following new goals

Proof step 2:
avol[n] = mapped(buf), n < # avol, abs(avol, bleb, wbuf, avol0, rofs) ⊦ avol0[n].mapped? ↔ true

Rule argument

Additional information