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Proof step 4 from proof abs-nobuffer (previous step)

# avol0 = # avol1, ∀ n. n < # avol1 → avol0[n] = avol1[n] ⊦ # avol0 = # avol1 ∧ (∀ n. n < # avol0 → avol0[n] = avol1[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# avol0 = # avol1, n < # avol1, ∀ n. n < # avol1 → avol0[n] = avol1[n] ⊦ avol0[n] = avol1[n]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic