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Proof step 26 from proof inv-format (previous step)

adr = adr0, avol = fill(mkavolume(# lpt2), unmapped), lpt = lpt2, m = m0, ns = ∅, plog = [], ebm-vol-inv(fill(mkavolume(# lpt2), unmapped)) ⊦ ⟪rofs := false⟫ ( # (wbuf.content:= mkbuf(EB_PAGE_SIZE)).content = EB_PAGE_SIZE ∧ (nobuffer ≠ nobuffer → nobuffer.leb < # lpt2 ∧ wbuf-cons(wbuf.content:= mkbuf(EB_PAGE_SIZE), unmapped, rofs)) ∧ EB_PAGE_SIZE = EB_PAGE_SIZE)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ (wbuf.content:= buf).content = buf; (s)% ⊦ # mkbuf(n) = n; (s)