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Proof step 40 from proof inv-read-buf (previous step)

# buf1 = EB_PAGE_SIZE, # lpt = # avol, avol[m3] = mapped(buf2), buf0 = buf, err = err0, n0 = 0, m3 < # avol, ebm-vol-inv(avol), m0 + n ≤ LEB_SIZE, n ≤ # buf, bleb ≠ nobuffer → bleb.leb < # avol ∧ wbuf-cons(mkwbuf(buf1, m5, m4), avol[bleb.leb], rofs), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ err = ESUCCESS, ∃ buf. # buf = # buf0 ∧ range=(buf0, 0, buf, 0, n0) ∧ range=(buf0, n0 + n, buf, n0 + n, # buf0 - n0 + n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 41:
# lpt = # avol, # buf1 = EB_PAGE_SIZE, avol[m3] = mapped(buf2), m3 < # avol, ebm-vol-inv(avol), n ≤ # buf, m0 + n ≤ LEB_SIZE, ⌊err0⌋ , bleb ≠ nobuffer → bleb.leb < # avol ∧ wbuf-cons(mkwbuf(buf1, m5, m4), avol[bleb.leb], rofs) ⊦ ∃ buf0. # buf0 = # buf ∧ range=(buf, n, buf0, n, # buf - n)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)% ⊦ 0 ≤ m; (s)% ⊦ range=(buf, n0, buf0, n1, 0) ↔ n0 ≤ # buf ∧ n1 ≤ # buf0; (s)% ⊦ ⌊err⌋ → err ≠ ESUCCESS; (s)