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Proof step 92 from proof refine-add-log-leb (previous step)

# buf0 = EB_PAGE_SIZE, # lpt0 = # avol1, # avol0 = # avol1, rofs ↔ false, avol1[m5] = mapped(buf), adr = adr0, avol = avol1, bleb = bleb0, bleb0 = bleb1, lpt = lpt0, m = m2, m0 = # avol1[m5].data, m1 = m5, ns = ns0, plog = plog0, plog1 = plog0, avol1[m5].mapped?, m5 < # avol1, abs(avol1, bleb1, mkwbuf(buf0, m4, m3), avol0, false), awbuf-inv(avol1, bleb1), ebm-vol-inv(avol0), synced(avol1), ⌊err0⌋ , bleb1 ≠ buffered(m5) → bleb1 = nobuffer ∨ m3 = 0 → avol0[m5].mapped?, bleb1 ≠ nobuffer → bleb1.leb < # avol1 ∧ wbuf-cons(mkwbuf(buf0, m4, m3), avol0[bleb1.leb], false), bleb1 = buffered(m5) ∨ (bleb1 = nobuffer ∨ m3 = 0) ∧ avol0[m5].mapped? ∧ # buf = # avol0[m5].data ⊦ ⟨if m1 < # avol ∧ avol[m1].mapped? ∧ m0 = # avol[m1].data ∧ synced(avol) then {fail_or_success#(; ; err); if err = ESUCCESS then plog := plog + m1, bleb := buffered(m1)} else abort⟩ (bleb = bleb1 ∧ plog = plog1 ∧ err0 = err)

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Proof step 93:
# avol0 = # avol1, # lpt0 = # avol1, # buf0 = EB_PAGE_SIZE, rofs ↔ false, avol1[m5] = mapped(buf), adr = adr0, avol = avol1, bleb = bleb0, bleb0 = bleb1, lpt = lpt0, m = m2, m0 = # avol1[m5].data, m1 = m5, ns = ns0, plog = plog0, plog1 = plog0, avol1[m5].mapped?, m5 < # avol1, abs(avol1, bleb1, mkwbuf(buf0, m4, m3), avol0, false), awbuf-inv(avol1, bleb1), ebm-vol-inv(avol0), synced(avol1), ⌊err0⌋ , bleb1 ≠ nobuffer → bleb1.leb < # avol1 ∧ wbuf-cons(mkwbuf(buf0, m4, m3), avol0[bleb1.leb], false), bleb1 ≠ buffered(m5) → bleb1 = nobuffer ∨ m3 = 0 → avol0[m5].mapped?, bleb1 = buffered(m5) ∨ (bleb1 = nobuffer ∨ m3 = 0) ∧ avol0[m5].mapped? ∧ # buf = # avol0[m5].data ⊦ ⟨fail_or_success#(; ; err); if err = ESUCCESS then plog := plog + m1, bleb := buffered(m1)⟩ (bleb = bleb1 ∧ plog = plog1 ∧ err0 = err)

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ mapped(buf).mapped?; (s)