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Proof step 126 from proof refine-read-buf (previous step)

# buf2 = EB_PAGE_SIZE, # lpt0 = # avol1, # avol0 = # avol1, # buf3 = n4 + n2, n1 + n5 = n4 + n2, (n0 + # buf4) + n3 + n2 = LEB_SIZE, avol1[m2] = mapped(buf4 + subarray(buf2, 0, n2 + n0)), avol0[m2] = mapped(buf4), n < n2 + n4, n0 < EB_PAGE_SIZE, n2 + n0 < EB_PAGE_SIZE, m2 < # avol1, n < n4 + n2, n < # subarray(subarray(buf2, 0, n2 + n0) + mkempbuf(n3), n0, n1) + # subarray(buf3, n1, n5), awbuf-inv(avol1, buffered(m2)), ebm-vol-inv(avol0), is-aligned(# buf4, EB_PAGE_SIZE), n2 ≤ n1, # buf4 ≤ LEB_SIZE, n1 ≤ n2 + n3 ⊦ (n < n2 ⊃ buf2[n0 + n];subarray(mkempbuf(n1) + subarray(buf3, n1, n5), n2, n4)[n - n2]) = (n < # subarray(subarray(buf2, 0, n2 + n0) + mkempbuf(n3), n0, n1) ⊃ subarray(subarray(buf2, 0, n2 + n0) + mkempbuf(n3), n0, n1)[n] ;subarray(buf3, n1, n5)[n - # subarray(subarray(buf2, 0, n2 + n0) + mkempbuf(n3), n0, n1)] ), EB_PAGE_SIZE = 1, n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 127:
# buf3 = n4 + n2, # avol0 = # avol1, # lpt0 = # avol1, # buf2 = EB_PAGE_SIZE, (n0 + # buf4) + n3 + n2 = LEB_SIZE, n1 + n5 = n4 + n2, avol0[m2] = mapped(buf4), avol1[m2] = mapped(buf4 + subarray(buf2, 0, n2 + n0)), m2 < # avol1, n2 + n0 < EB_PAGE_SIZE, n0 < EB_PAGE_SIZE, n < n2 + n4, n < n4 + n2, awbuf-inv(avol1, buffered(m2)), ebm-vol-inv(avol0), is-aligned(# buf4, EB_PAGE_SIZE), n1 ≤ n2 + n3, # buf4 ≤ LEB_SIZE, n2 ≤ n1 ⊦ (n < n2 ⊃ buf2[n0 + n];subarray(mkempbuf(n1) + subarray(buf3, n1, n5), n2, n4)[n - n2]) = (n < n1 ⊃ (subarray(buf2, 0, n2 + n0) + mkempbuf(n3))[n0 + n];subarray(buf3, n1, n5)[n - n1]), EB_PAGE_SIZE = 1, n0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ n0 < n → subarray(buf, m, n)[n0] = buf[m + n0]; (s)% ⊦ # subarray(buf, m, n) = n; (s)