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Proof step 135 from proof refine-read-buf (previous step)

# buf2 = EB_PAGE_SIZE, # lpt0 = # avol1, # avol0 = # avol1, # buf3 = n4 + n2, n1 + n5 = n4 + n2, (n0 + # buf4) + n3 + n2 = LEB_SIZE, avol1[m2] = mapped(buf4 + subarray(buf2, 0, n2 + n0)), avol0[m2] = mapped(buf4), n < n4 + n2, n < n2 + n4, n0 < EB_PAGE_SIZE, n2 + n0 < EB_PAGE_SIZE, m2 < # avol1, awbuf-inv(avol1, buffered(m2)), ebm-vol-inv(avol0), is-aligned(# buf4, EB_PAGE_SIZE), n2 ≤ n, n2 ≤ n1, # buf4 ≤ LEB_SIZE, n1 ≤ n2 + n3 ⊦ EB_PAGE_SIZE = 1, subarray(mkempbuf(n1) + subarray(buf3, n1, n5), n2, n4)[n - n2] = (n < n1 ⊃ (subarray(buf2, 0, n2 + n0) + mkempbuf(n3))[n0 + n];subarray(buf3, n1, n5)[n - n1]), n0 = 0, n4 = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 136:
# buf3 = n4 + n2, # avol0 = # avol1, # lpt0 = # avol1, # buf2 = EB_PAGE_SIZE, (n0 + # buf4) + n3 + n2 = LEB_SIZE, n1 + n5 = n4 + n2, avol0[m2] = mapped(buf4), avol1[m2] = mapped(buf4 + subarray(buf2, 0, n2 + n0)), n = n6 + n2, m2 < # avol1, n2 + n0 < EB_PAGE_SIZE, n0 < EB_PAGE_SIZE, n < n2 + n4, n < n4 + n2, awbuf-inv(avol1, buffered(m2)), ebm-vol-inv(avol0), is-aligned(# buf4, EB_PAGE_SIZE), n1 ≤ n2 + n3, # buf4 ≤ LEB_SIZE, n2 ≤ n1, n2 ≤ n ⊦ EB_PAGE_SIZE = 1, subarray(mkempbuf(n1) + subarray(buf3, n1, n5), n2, n4)[n6] = (n < n1 ⊃ (subarray(buf2, 0, n2 + n0) + mkempbuf(n3))[n0 + n];subarray(buf3, n1, n5)[n - n1]), n0 = 0, n4 = 0

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [n, m, n0] → [n2, n, n6]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n2, n, n6