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Proof step 198 from proof refine-read-buf (previous step)

# buf3 = n5 + n1, # avol0 = # avol1, # lpt0 = # avol1, # buf2 = EB_PAGE_SIZE, n1 + n5 = n4 + min(n1, n2), LEB_SIZE = n0 + # buf4, avol0[m2] = mapped(buf4), avol1[m2] = mapped(buf4), m0 = n3 + m6, subarray(buf2, 0, n2 + n3) = subarray(buf4, m6, n2 + n3), m6 < # buf4, m0 + n2 < # buf4, m0 < EB_PAGE_SIZE + m6, m2 < # avol1, n2 + n3 < EB_PAGE_SIZE, m0 < # buf4, m0 < LEB_SIZE, m6 < LEB_SIZE, m6 < m0, m0 + n2 < LEB_SIZE, m6 + 1 < # buf4, m6 + 1 < LEB_SIZE, awbuf-inv(avol1, buffered(m2)), ebm-vol-inv(avol0), is-aligned(m6, EB_PAGE_SIZE), m0 + n1 ≤ LEB_SIZE, m0 + min(n1, n2) ≤ EB_PAGE_SIZE + m6, # buf4 ≤ LEB_SIZE, m6 ≤ m0 + n1, min(n1, n2) ≤ n1 + n5, m6 ≤ m0 ⊦ subarray(buf2, n3, min(n1, n2)) + subarray(subarray(buf4 + mkempbuf(n0), m0, n1) + subarray(buf3, n1, n5), min(n1, n2), n4) = subarray(buf4 + mkempbuf(n0), m0, n1) + subarray(buf3, n1, n5), EB_PAGE_SIZE = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 199:
# buf3 = n5 + n1, # avol0 = # avol1, # lpt0 = # avol1, # buf2 = EB_PAGE_SIZE, n1 + n5 = n4 + min(n1, n2), LEB_SIZE = n0 + # buf4, avol0[m2] = mapped(buf4), avol1[m2] = mapped(buf4), subarray(buf2, 0, n2 + n3) = subarray(buf4, m6, n2 + n3), n3 + m6 < LEB_SIZE, (n3 + m6) + n2 < LEB_SIZE, n3 < EB_PAGE_SIZE, m2 < # avol1, n2 + n3 < EB_PAGE_SIZE, n3 + m6 < # buf4, m6 < LEB_SIZE, m6 + 1 < # buf4, m6 + 1 < LEB_SIZE, m6 < # buf4, (n3 + m6) + n2 < # buf4, awbuf-inv(avol1, buffered(m2)), ebm-vol-inv(avol0), is-aligned(m6, EB_PAGE_SIZE), (n3 + m6) + n1 ≤ LEB_SIZE, n3 + min(n1, n2) ≤ EB_PAGE_SIZE, # buf4 ≤ LEB_SIZE, min(n1, n2) ≤ n1 + n5 ⊦ subarray(buf2, n3, min(n1, n2)) + subarray(subarray(buf4 + mkempbuf(n0), n3 + m6, n1) + subarray(buf3, n1, n5), min(n1, n2), n4) = subarray(buf4 + mkempbuf(n0), n3 + m6, n1) + subarray(buf3, n1, n5), EB_PAGE_SIZE = 1, n3 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m + n < m0 → m + n < m0 + n0; (s)%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic% ⊦ m + n < m + n0 ↔ n < n0; (s)% ⊦ m < m + n ↔ n ≠ 0; (s)% ⊦ m + n ≤ m + n0 ↔ n ≤ n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)% ⊦ m < n → m ≤ n; (s)