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Proof step 306 from proof refine-read-buf (previous step)

# buf2 = EB_PAGE_SIZE, # lpt0 = # avol1, # avol0 = # avol1, LEB_SIZE = n0 + # buf4, avol1[m2] = mapped(buf1), avol0[m2] = mapped(buf4), m2 < # avol1, abs(avol1, bleb, mkwbuf(buf2, m6, m4), avol0, rofs), awbuf-inv(avol1, bleb), ebm-vol-inv(avol0), # buf4 ≤ LEB_SIZE, n ≤ # buf3, m0 + n ≤ LEB_SIZE, bleb ≠ nobuffer → bleb.leb < # avol1 ∧ avol0[bleb.leb].mapped? ∧ m4 < EB_PAGE_SIZE ∧ (¬ rofs → # avol0[bleb.leb].data = m6) ∧ (rofs → m6 ≤ # avol0[bleb.leb].data) ∧ is-aligned(m6, EB_PAGE_SIZE) ⊦ ⟨err := ESUCCESS; buf := copy(buf4 + mkempbuf(n0), m0, buf3, 0, n); if err = ESUCCESS then buf3 := copy(avol1[m2].data + mkempbuf(LEB_SIZE - # avol1[m2].data), m0, buf3, 0, n) else choose buf with # buf = # buf3 ∧ range=(buf, n, buf3, n, # buf3 - n) in buf3 := buf⟩ (buf = buf3 ∧ ESUCCESS = err), buffered(m2) = bleb ∧ m0 ≤ m6 + m4 ∧ m6 ≤ m0 + n

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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