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Proof step 318 from proof refine-read-buf (previous step)

# avol0 = # avol1, # lpt0 = # avol1, # buf2 = EB_PAGE_SIZE, LEB_SIZE = n1 + # buf1, LEB_SIZE = n0 + # buf4, avol1[m2] = mapped(buf1), avol0[m2] = mapped(buf4), avol0[n2] = mapped(buf), m4 < EB_PAGE_SIZE, m2 < # avol1, n2 < # avol1, awbuf-inv(avol1, buffered(n2)), ebm-vol-inv(avol0), is-aligned(m6, EB_PAGE_SIZE), # buf1 ≤ LEB_SIZE, n ≤ # buf3, # buf4 ≤ LEB_SIZE, m0 + n ≤ LEB_SIZE, ¬ rofs → # buf = m6, rofs → m6 ≤ # buf, ∀ n3. n3 < # avol1 → (n3 ≠ n2 → avol1[n3] = avol0[n3]) ∧ (¬ rofs ∧ n3 = n2 → avol1[n2] = mapped(buf + subarray(buf2, 0, m4))) ∧ ( rofs ∧ n3 = n2 → m6 = # buf ∧ avol1[n2] = mapped(buf + subarray(buf2, 0, m4)) ∨ m6 < # buf ∧ m6 + m4 < # buf ∧ avol1[n2] = mapped(buf) ∧ subarray(buf2, 0, m4) = subarray(buf, m6, m4)) ⊦ copy(buf4 + mkempbuf(n0), m0, buf3, 0, n) = copy(buf1 + mkempbuf(n1), m0, buf3, 0, n), m2 = n2 ∧ m0 ≤ m6 + m4 ∧ m6 ≤ m0 + n

User applied rule all left

And obtained the following new goals

Proof step 319:
# buf2 = EB_PAGE_SIZE, # lpt0 = # avol1, # avol0 = # avol1, LEB_SIZE = n0 + # buf4, LEB_SIZE = n1 + # buf1, avol0[n2] = mapped(buf), avol0[m2] = mapped(buf4), avol1[m2] = mapped(buf1), n2 < # avol1, m2 < # avol1, m4 < EB_PAGE_SIZE, awbuf-inv(avol1, buffered(n2)), ebm-vol-inv(avol0), is-aligned(m6, EB_PAGE_SIZE), m0 + n ≤ LEB_SIZE, # buf4 ≤ LEB_SIZE, n ≤ # buf3, # buf1 ≤ LEB_SIZE, rofs → m6 ≤ # buf, ¬ rofs → # buf = m6, m2 < # avol1 → (m2 ≠ n2 → avol1[m2] = avol0[m2]) ∧ (¬ rofs ∧ m2 = n2 → avol1[n2] = mapped(buf + subarray(buf2, 0, m4))) ∧ ( rofs ∧ m2 = n2 → m6 = # buf ∧ avol1[n2] = mapped(buf + subarray(buf2, 0, m4)) ∨ m6 < # buf ∧ m6 + m4 < # buf ∧ avol1[n2] = mapped(buf) ∧ subarray(buf2, 0, m4) = subarray(buf, m6, m4)) ⊦ copy(buf4 + mkempbuf(n0), m0, buf3, 0, n) = copy(buf1 + mkempbuf(n1), m0, buf3, 0, n), m2 = n2 ∧ m0 ≤ m6 + m4 ∧ m6 ≤ m0 + n

Rule argument

pos: left 21 terms: m2 abort: F discard: T computed: T

Additional information

Used terms: m2