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Proof step 358 from proof refine-read-buf (previous step)

# buf = # buf0, # avol0 = # avol1, # lpt0 = # avol1, # buf2 = EB_PAGE_SIZE, avol1[m2] = mapped(buf1), buf0 = buf3, err = err0, n0 = 0, m2 < # avol1, abs(avol1, bleb, mkwbuf(buf2, m6, m4), avol0, rofs), awbuf-inv(avol1, bleb), ebm-vol-inv(avol0), range=(buf0, 0, buf, 0, n0), range=(buf0, n0 + n, buf, n0 + n, # buf0 - n0 + n), n ≤ # buf3, m0 + n ≤ LEB_SIZE, bleb ≠ nobuffer → bleb.leb < # avol1 ∧ avol0[bleb.leb].mapped? ∧ m4 < EB_PAGE_SIZE ∧ (¬ rofs → # avol0[bleb.leb].data = m6) ∧ (rofs → m6 ≤ # avol0[bleb.leb].data) ∧ is-aligned(m6, EB_PAGE_SIZE), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪buf0 := buf; buf4 := buf0; if err = ESUCCESS ∧ buffered(m2) = bleb ∧ m0 ≤ m6 + m4 ∧ m6 ≤ m0 + n then let m1 = (m0 ≤ m6 ⊃ 0;m0 - m6), m = (m0 ≤ m6 ⊃ m6 - m0;0) in buf4 := copy(buf2, m1, buf4, m, min(n - m, m4 - m1))⟫ ⟨awbuf_read_buf#(m2, m0, n, adr0, m5, plog0, avol1, lpt0, ns0, bleb, rofs; buf3; err1)⟩ (buf4 = buf3 ∧ err = err1), err = ESUCCESS

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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