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Proof step 383 from proof refine-read-buf (previous step)

# avol0 = # avol1, # lpt0 = # avol1, # buf2 = EB_PAGE_SIZE, avol1[m2] = mapped(buf1), buf0 = buf3, err = err0, n0 = 0, m2 < # avol1, abs(avol1, bleb, mkwbuf(buf2, m6, m4), avol0, rofs), awbuf-inv(avol1, bleb), ebm-vol-inv(avol0), n ≤ # buf3, m0 + n ≤ LEB_SIZE, bleb ≠ nobuffer → bleb.leb < # avol1 ∧ avol0[bleb.leb].mapped? ∧ m4 < EB_PAGE_SIZE ∧ (¬ rofs → # avol0[bleb.leb].data = m6) ∧ (rofs → m6 ≤ # avol0[bleb.leb].data) ∧ is-aligned(m6, EB_PAGE_SIZE), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ err = ESUCCESS, ∀ buf. # buf = # buf0 → range=(buf0, 0, buf, 0, n0) → # buf0 ≥ n0 + n

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ n ≥ m ↔ m ≤ n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)% ⊦ 0 ≤ m; (s)% ⊦ range=(buf, n0, buf0, n1, 0) ↔ n0 ≤ # buf ∧ n1 ≤ # buf0; (s)