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Proof step 192 from proof refine-write-buf (previous step)

# buf1 = EB_PAGE_SIZE, # lpt0 = # avol1, # avol0 = # avol1, rofs ↔ false, avol0[m4] = mapped(buf2), align↓(m2 + n3, EB_PAGE_SIZE) = n + m2, m = buffered(m4).leb, buffered(m4).isbuf?, m4 < # avol1, m2 < EB_PAGE_SIZE, abs(avol1, buffered(m4), mkwbuf(buf1, # buf2, m2), avol0, false), awbuf-inv(avol1, buffered(m4)), ebm-vol-inv(avol0), is-aligned(# buf2, EB_PAGE_SIZE), is-aligned(n + m2, EB_PAGE_SIZE), # buf2 + n + m2 ≤ LEB_SIZE, # buf2 + m2 + n3 ≤ LEB_SIZE, EB_PAGE_SIZE ≤ m2 + n3, n3 ≤ # buf3, # avol1[m4].data + n3 ≤ LEB_SIZE, n ≤ # buf3, ⌊err1⌋ ⊦ ⟨err := err1; if err = ESUCCESS then avol1[m] := mapped(avol1[m].data + subarray(buf3, 0, n3)) else { choose n with n ≠ 0 ∧ n < n3 ∧ is-aligned(# avol1[m].data + n, EB_PAGE_SIZE) in avol1[m] := mapped(avol1[m].data + subarray(buf3, 0, n)) ifnone skip or skip; rofs := true}⟩ (abs(avol1, buffered(m4), mkwbuf(buf1, # buf2, m2), avol0, true) ∧ rofs ∧ err1 = err), n + m2 = 0, n3 = 0

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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