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Proof step 9 from proof at-copy (previous step)

m0 < # ar1, ∀ m0, ar1, ar0, n, n0. m0 < # ar1 → copy(ar0, n, ar1, n0, m1)[m0] = (m0 < n0 ∨ n0 + m1 ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0]) ⊦ copy(ar0, n, ar1, n0, m1)[m0] = (m0 < n0 ∨ n0 + m1 < m0 ⊃ ar1[m0];ar0[m0 + n - n0]), m0 = n0 + m1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m0, ar1, ar0, n, n0

Additional information

Used simplifier rules: ⊦ m ≠ n → (m ≤ n ↔ m < n); (s) Used terms: m0, ar1, ar0, n, n0