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Proof step 7 from proof copy-coalesce (previous step)

n1 < # ar2, m0 + n ≤ # ar1, m0 ≤ # ar1 ⊦ copy(ar0, n0, ar1, 0, # ar1)[n1 + n - n2] = (n1 < n2 ∨ n2 + m0 ≤ n1 ⊃ ar2[n1];ar0[n1 + n0 + n - n2]), n1 < n2, n2 + m0 ≤ n1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
n2 < # ar2, n1 < n2 + m0, n1 < # ar2, n2 ≤ n1, m0 + n ≤ # ar1, m0 ≤ # ar1 ⊦ copy(ar0, n0, ar1, 0, # ar1)[(n1 - n2) + n] = ar0[(n1 - n2) + n0 + n], m0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < m + n ↔ n ≠ 0; (s)% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n ≤ m → m + n0 - n = (m - n) + n0; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n ↔ ¬ n < m; (ss)