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Proof step 9 from proof copy-coalesce (previous step)

n1 = n3 + n2, n1 < # ar2, n1 < n2 + m0, n2 < # ar2, m0 ≤ # ar1, m0 + n ≤ # ar1, n2 ≤ n1 ⊦ copy(ar0, n0, ar1, 0, # ar1)[n3 + n] = ar0[n3 + n0 + n], m0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
n3 + n2 < # ar2, n2 < # ar2, n3 < m0, n3 < # ar1, m0 + n ≤ # ar1, m0 ≤ # ar1 ⊦ copy(ar0, n0, ar1, 0, # ar1)[n3 + n] = ar0[n3 + n0 + n]

Rule argument

Additional information

Used simplifier rules: fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)% ⊦ m + n < m + n0 ↔ n < n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)