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Proof step 17 from proof rev-at-h (previous step)

# ar = n2 + n1 + 1, n1 < # ar, # rev(ar, n1) < # ar, # rev(ar, n1) ≤ n1, # rev(ar, n1) ≤ n2 + n1, ∀ ar, n0, m. # ar = n0 + m + 1 ∧ m < # ar ∧ m < n1 ∧ n1 ≤ # ar → rev(ar, n1)[m] = ar[n0] ⊦ rev(ar, n1)[n1, ar[n2]][n1] = ar[n2]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ n ≤ # ar → # rev(ar, n) = # ar

Rule argument

spec: <toplevel> name: rev-size-h seq: ⊦ n ≤ # ar → # rev(ar, n) = # ar subst: [n, ar] → [n1, ar] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n; (s)% ⊦ m < n → (n ≤ m ↔ false); (s) Used terms: n1, ar