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Proof step 5 from proof rev-at (previous step)

# ar = n0 + n + 1, n < # ar ⊦ rev(ar)[n] = ar[n0]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ rev(ar) = rev(ar, # ar)
Proof step 7:
# ar = n0 + n + 1, n < # ar ⊦ rev(ar, # ar)[n] = ar[n0]

Rule argument

spec: <toplevel> name: rev seq: ⊦ rev(ar) = rev(ar, # ar) subst: [ar] → [ar] flags: <all paths>

Additional information

Used terms: ar