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Proof step 11 from proof rev-rev (previous step)

# ar = n0 + n + 1, n < # ar ⊦ rev(ar)[n0] = ar[n], n0 < # ar

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
# ar = n0 + n + 1, n < # ar, n < n0, # ar ≤ n0 ⊦ rev(ar)[n0] = ar[n]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat% ⊦ m < n ↔ ¬ n ≤ m; (ss)