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Proof step 8 from proof rev-rev (previous step)

# ar = n0 + n + 1, n < # ar, n + 1 ≤ # ar ⊦ rev(ar)[n0] = ar[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
# ar = n0 + n + 1, n < # ar ⊦ rev(ar)[n0] = ar[n]

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m + n < m; (s)% ⊦ m < n + 1 ↔ ¬ n < m; (s)%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + 1 ≤ n ↔ m < n; (s)