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Proof step 1 from proof subarray-copy-higher (conclusion)

m0 + m1 ≤ n1, m0 + m1 ≤ # ar ⊦ subarray(copy(ar0, n0, ar, n1, n2), m0, m1) = subarray(ar, m0, m1)

System applied rule normalize

And obtained the following new goals

Proof step 2:
m0 + m1 ≤ # ar, m0 + m1 ≤ n1 ⊦ subarray(copy(ar0, n0, ar, n1, n2), m0, m1) = subarray(ar, m0, m1)

Rule argument

Additional information