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Proof step 1 from proof subarray-longer-eq-eq (conclusion)

⊦ subarray(ar0, 0, n + m) = subarray(ar1, 0, n + m) → (subarray(ar0, 0, n) = subarray(ar1, 0, n) ↔ true)

System applied rule normalize

And obtained the following new goals

Proof step 2:
subarray(ar0, 0, n + m) = subarray(ar1, 0, n + m) ⊦ subarray(ar0, 0, n) = subarray(ar1, 0, n) ↔ true

Rule argument

Additional information