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Proof step 1 from proof subarray-subarray-elim-0 (conclusion)

n2 ≤ n1 ⊦ n1 < # ar0 → subarray(subarray(ar0, 0, n1), 0, n2) = subarray(ar0, 0, n2)

System applied rule normalize

And obtained the following new goals

Proof step 2:
n1 < # ar0, n2 ≤ n1 ⊦ subarray(subarray(ar0, 0, n1), 0, n2) = subarray(ar0, 0, n2)

Rule argument

Additional information