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Proof step 5 from proof cputput-reverse (previous step)

⊦ m = n, # ar[m, a][n, b] = # ar[n, b][m, a] ∧ (∀ n0. n0 < # ar[m, a][n, b] → ar[m, a][n, b][n0] = ar[n, b][m, a][n0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
n0 < # ar ⊦ ar[m, a][n, b][n0] = ar[n, b][m, a][n0], m = n

Rule argument

Additional information

Used simplifier rules: Size-put: ⊦ # ar[n, a] = # ar;% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic