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Proof step 7 from proof cputput-reverse (previous step)

n0 < # ar ⊦ ar[m, a][n, b][n0] = ar[n, b][m, a][n0], m = n, n0 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
n0 < # ar ⊦ ar[m, a][n0] = ar[n, b][m, a][n0], m = n, n0 = n

Rule argument

Additional information

Used simplifier rules: cngetput: m ≠ n ⊦ ar[m, a][n] = ar[n];