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Proof step 5 from proof nuni-01 (previous step)

unique_al((p ' + ay0) + (a × d)' + az), a ∈ az, ∀ a0, d0, az0. ¬ unique_al(ay0 + (a0 × d0)' + az0) ∨ ¬ a0 ∈ az0 ⊦

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a, d, az abort: F discard: T computed: T

Additional information

Used simplifier rules: not: ⊦ ¬ unique_al(ax) → ¬ unique_al(p ' + ax);%a: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; from specification list[assoclist] Used terms: a, d, az