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Proof step 10 from proof bag-rm-add-eq (previous step)

a ∈ bag ⊦ ∀ a0. count(a0, (bag -- a) ++ a) = count(a0, bag)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
a ∈ bag ⊦ count(a0, (bag -- a) ++ a) = count(a0, bag)

Rule argument

Additional information