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Proof step 15 from proof bag-rm-add-eq (
previous step
)
a0 = a, a ∈ bag ⊦ 1 + (count(a0, bag) - (a0 = a ∧ count(a, bag) ≠ 0 ⊃ 1;0)) = count(a0, bag)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 16
:
a ∈ bag ⊦ 1 + (count(a, bag) - (count(a, bag) ≠ 0 ⊃ 1;0)) = count(a, bag)
Rule argument
Additional information