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Proof step 17 from proof bag-rm-add-eq (previous step)

count(a, bag) = 0, a ∈ bag ⊦ 1 + (count(a, bag) - 0) = count(a, bag)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
count(a, bag) = 0, a ∈ bag ⊦

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m = m + n ↔ n = 0; (s)% ⊦ m - 0 = m; (s)