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Proof step 5 from proof in-add (previous step)

⊦ a = b, count(a, bag ++ b) = 0, a ∈ bag

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ a = b, count(a, bag) = 0, a ∈ bag

Rule argument

Additional information

Used simplifier rules: ⊦ a ≠ b → count(a, bag ++ b) = count(a, bag); (s)